\(\int \frac {(A+B \cos (c+d x)+C \cos ^2(c+d x)) \sec ^4(c+d x)}{(a+a \cos (c+d x))^{3/2}} \, dx\) [417]
Optimal result
Integrand size = 43, antiderivative size = 284 \[
\int \frac {\left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^4(c+d x)}{(a+a \cos (c+d x))^{3/2}} \, dx=-\frac {(47 A-38 B+24 C) \text {arctanh}\left (\frac {\sqrt {a} \sin (c+d x)}{\sqrt {a+a \cos (c+d x)}}\right )}{8 a^{3/2} d}+\frac {(17 A-13 B+9 C) \text {arctanh}\left (\frac {\sqrt {a} \sin (c+d x)}{\sqrt {2} \sqrt {a+a \cos (c+d x)}}\right )}{2 \sqrt {2} a^{3/2} d}+\frac {(21 A-14 B+12 C) \tan (c+d x)}{8 a d \sqrt {a+a \cos (c+d x)}}-\frac {(13 A-12 B+6 C) \sec (c+d x) \tan (c+d x)}{12 a d \sqrt {a+a \cos (c+d x)}}-\frac {(A-B+C) \sec ^2(c+d x) \tan (c+d x)}{2 d (a+a \cos (c+d x))^{3/2}}+\frac {(5 A-3 B+3 C) \sec ^2(c+d x) \tan (c+d x)}{6 a d \sqrt {a+a \cos (c+d x)}}
\]
[Out]
-1/8*(47*A-38*B+24*C)*arctanh(sin(d*x+c)*a^(1/2)/(a+a*cos(d*x+c))^(1/2))/a^(3/2)/d+1/4*(17*A-13*B+9*C)*arctanh
(1/2*sin(d*x+c)*a^(1/2)*2^(1/2)/(a+a*cos(d*x+c))^(1/2))/a^(3/2)/d*2^(1/2)-1/2*(A-B+C)*sec(d*x+c)^2*tan(d*x+c)/
d/(a+a*cos(d*x+c))^(3/2)+1/8*(21*A-14*B+12*C)*tan(d*x+c)/a/d/(a+a*cos(d*x+c))^(1/2)-1/12*(13*A-12*B+6*C)*sec(d
*x+c)*tan(d*x+c)/a/d/(a+a*cos(d*x+c))^(1/2)+1/6*(5*A-3*B+3*C)*sec(d*x+c)^2*tan(d*x+c)/a/d/(a+a*cos(d*x+c))^(1/
2)
Rubi [A] (verified)
Time = 1.16 (sec) , antiderivative size = 284, normalized size of antiderivative = 1.00, number of
steps used = 9, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.140, Rules used = {3120, 3063, 3064, 2728, 212,
2852} \[
\int \frac {\left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^4(c+d x)}{(a+a \cos (c+d x))^{3/2}} \, dx=-\frac {(47 A-38 B+24 C) \text {arctanh}\left (\frac {\sqrt {a} \sin (c+d x)}{\sqrt {a \cos (c+d x)+a}}\right )}{8 a^{3/2} d}+\frac {(17 A-13 B+9 C) \text {arctanh}\left (\frac {\sqrt {a} \sin (c+d x)}{\sqrt {2} \sqrt {a \cos (c+d x)+a}}\right )}{2 \sqrt {2} a^{3/2} d}+\frac {(21 A-14 B+12 C) \tan (c+d x)}{8 a d \sqrt {a \cos (c+d x)+a}}+\frac {(5 A-3 B+3 C) \tan (c+d x) \sec ^2(c+d x)}{6 a d \sqrt {a \cos (c+d x)+a}}-\frac {(A-B+C) \tan (c+d x) \sec ^2(c+d x)}{2 d (a \cos (c+d x)+a)^{3/2}}-\frac {(13 A-12 B+6 C) \tan (c+d x) \sec (c+d x)}{12 a d \sqrt {a \cos (c+d x)+a}}
\]
[In]
Int[((A + B*Cos[c + d*x] + C*Cos[c + d*x]^2)*Sec[c + d*x]^4)/(a + a*Cos[c + d*x])^(3/2),x]
[Out]
-1/8*((47*A - 38*B + 24*C)*ArcTanh[(Sqrt[a]*Sin[c + d*x])/Sqrt[a + a*Cos[c + d*x]]])/(a^(3/2)*d) + ((17*A - 13
*B + 9*C)*ArcTanh[(Sqrt[a]*Sin[c + d*x])/(Sqrt[2]*Sqrt[a + a*Cos[c + d*x]])])/(2*Sqrt[2]*a^(3/2)*d) + ((21*A -
14*B + 12*C)*Tan[c + d*x])/(8*a*d*Sqrt[a + a*Cos[c + d*x]]) - ((13*A - 12*B + 6*C)*Sec[c + d*x]*Tan[c + d*x])
/(12*a*d*Sqrt[a + a*Cos[c + d*x]]) - ((A - B + C)*Sec[c + d*x]^2*Tan[c + d*x])/(2*d*(a + a*Cos[c + d*x])^(3/2)
) + ((5*A - 3*B + 3*C)*Sec[c + d*x]^2*Tan[c + d*x])/(6*a*d*Sqrt[a + a*Cos[c + d*x]])
Rule 212
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])
Rule 2728
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[-2/d, Subst[Int[1/(2*a - x^2), x], x, b*(C
os[c + d*x]/Sqrt[a + b*Sin[c + d*x]])], x] /; FreeQ[{a, b, c, d}, x] && EqQ[a^2 - b^2, 0]
Rule 2852
Int[Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]]/((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Dist[-2*(
b/f), Subst[Int[1/(b*c + a*d - d*x^2), x], x, b*(Cos[e + f*x]/Sqrt[a + b*Sin[e + f*x]])], x] /; FreeQ[{a, b, c
, d, e, f}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0]
Rule 3063
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_
.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(B*c - A*d)*Cos[e + f*x]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + f*x]
)^(n + 1)/(f*(n + 1)*(c^2 - d^2))), x] + Dist[1/(b*(n + 1)*(c^2 - d^2)), Int[(a + b*Sin[e + f*x])^m*(c + d*Sin
[e + f*x])^(n + 1)*Simp[A*(a*d*m + b*c*(n + 1)) - B*(a*c*m + b*d*(n + 1)) + b*(B*c - A*d)*(m + n + 2)*Sin[e +
f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, m}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2
- d^2, 0] && LtQ[n, -1] && (IntegerQ[n] || EqQ[m + 1/2, 0])
Rule 3064
Int[((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])/(Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]]*((c_.) + (d_.)*sin[(e_
.) + (f_.)*(x_)])), x_Symbol] :> Dist[(A*b - a*B)/(b*c - a*d), Int[1/Sqrt[a + b*Sin[e + f*x]], x], x] + Dist[(
B*c - A*d)/(b*c - a*d), Int[Sqrt[a + b*Sin[e + f*x]]/(c + d*Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f,
A, B}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0]
Rule 3120
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.)*((A_.) + (B_.)*s
in[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(a*A - b*B + a*C)*Cos[e + f*x]*(a
+ b*Sin[e + f*x])^m*((c + d*Sin[e + f*x])^(n + 1)/(f*(b*c - a*d)*(2*m + 1))), x] + Dist[1/(b*(b*c - a*d)*(2*m
+ 1)), Int[(a + b*Sin[e + f*x])^(m + 1)*(c + d*Sin[e + f*x])^n*Simp[A*(a*c*(m + 1) - b*d*(2*m + n + 2)) + B*(
b*c*m + a*d*(n + 1)) - C*(a*c*m + b*d*(n + 1)) + (d*(a*A - b*B)*(m + n + 2) + C*(b*c*(2*m + 1) - a*d*(m - n -
1)))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^
2, 0] && NeQ[c^2 - d^2, 0] && LtQ[m, -2^(-1)]
Rubi steps \begin{align*}
\text {integral}& = -\frac {(A-B+C) \sec ^2(c+d x) \tan (c+d x)}{2 d (a+a \cos (c+d x))^{3/2}}+\frac {\int \frac {\left (a (5 A-3 B+3 C)-\frac {1}{2} a (7 A-7 B+3 C) \cos (c+d x)\right ) \sec ^4(c+d x)}{\sqrt {a+a \cos (c+d x)}} \, dx}{2 a^2} \\ & = -\frac {(A-B+C) \sec ^2(c+d x) \tan (c+d x)}{2 d (a+a \cos (c+d x))^{3/2}}+\frac {(5 A-3 B+3 C) \sec ^2(c+d x) \tan (c+d x)}{6 a d \sqrt {a+a \cos (c+d x)}}+\frac {\int \frac {\left (-a^2 (13 A-12 B+6 C)+\frac {5}{2} a^2 (5 A-3 B+3 C) \cos (c+d x)\right ) \sec ^3(c+d x)}{\sqrt {a+a \cos (c+d x)}} \, dx}{6 a^3} \\ & = -\frac {(13 A-12 B+6 C) \sec (c+d x) \tan (c+d x)}{12 a d \sqrt {a+a \cos (c+d x)}}-\frac {(A-B+C) \sec ^2(c+d x) \tan (c+d x)}{2 d (a+a \cos (c+d x))^{3/2}}+\frac {(5 A-3 B+3 C) \sec ^2(c+d x) \tan (c+d x)}{6 a d \sqrt {a+a \cos (c+d x)}}+\frac {\int \frac {\left (\frac {3}{2} a^3 (21 A-14 B+12 C)-\frac {3}{2} a^3 (13 A-12 B+6 C) \cos (c+d x)\right ) \sec ^2(c+d x)}{\sqrt {a+a \cos (c+d x)}} \, dx}{12 a^4} \\ & = \frac {(21 A-14 B+12 C) \tan (c+d x)}{8 a d \sqrt {a+a \cos (c+d x)}}-\frac {(13 A-12 B+6 C) \sec (c+d x) \tan (c+d x)}{12 a d \sqrt {a+a \cos (c+d x)}}-\frac {(A-B+C) \sec ^2(c+d x) \tan (c+d x)}{2 d (a+a \cos (c+d x))^{3/2}}+\frac {(5 A-3 B+3 C) \sec ^2(c+d x) \tan (c+d x)}{6 a d \sqrt {a+a \cos (c+d x)}}+\frac {\int \frac {\left (-\frac {3}{4} a^4 (47 A-38 B+24 C)+\frac {3}{4} a^4 (21 A-14 B+12 C) \cos (c+d x)\right ) \sec (c+d x)}{\sqrt {a+a \cos (c+d x)}} \, dx}{12 a^5} \\ & = \frac {(21 A-14 B+12 C) \tan (c+d x)}{8 a d \sqrt {a+a \cos (c+d x)}}-\frac {(13 A-12 B+6 C) \sec (c+d x) \tan (c+d x)}{12 a d \sqrt {a+a \cos (c+d x)}}-\frac {(A-B+C) \sec ^2(c+d x) \tan (c+d x)}{2 d (a+a \cos (c+d x))^{3/2}}+\frac {(5 A-3 B+3 C) \sec ^2(c+d x) \tan (c+d x)}{6 a d \sqrt {a+a \cos (c+d x)}}+\frac {(17 A-13 B+9 C) \int \frac {1}{\sqrt {a+a \cos (c+d x)}} \, dx}{4 a}-\frac {(47 A-38 B+24 C) \int \sqrt {a+a \cos (c+d x)} \sec (c+d x) \, dx}{16 a^2} \\ & = \frac {(21 A-14 B+12 C) \tan (c+d x)}{8 a d \sqrt {a+a \cos (c+d x)}}-\frac {(13 A-12 B+6 C) \sec (c+d x) \tan (c+d x)}{12 a d \sqrt {a+a \cos (c+d x)}}-\frac {(A-B+C) \sec ^2(c+d x) \tan (c+d x)}{2 d (a+a \cos (c+d x))^{3/2}}+\frac {(5 A-3 B+3 C) \sec ^2(c+d x) \tan (c+d x)}{6 a d \sqrt {a+a \cos (c+d x)}}-\frac {(17 A-13 B+9 C) \text {Subst}\left (\int \frac {1}{2 a-x^2} \, dx,x,-\frac {a \sin (c+d x)}{\sqrt {a+a \cos (c+d x)}}\right )}{2 a d}+\frac {(47 A-38 B+24 C) \text {Subst}\left (\int \frac {1}{a-x^2} \, dx,x,-\frac {a \sin (c+d x)}{\sqrt {a+a \cos (c+d x)}}\right )}{8 a d} \\ & = -\frac {(47 A-38 B+24 C) \text {arctanh}\left (\frac {\sqrt {a} \sin (c+d x)}{\sqrt {a+a \cos (c+d x)}}\right )}{8 a^{3/2} d}+\frac {(17 A-13 B+9 C) \text {arctanh}\left (\frac {\sqrt {a} \sin (c+d x)}{\sqrt {2} \sqrt {a+a \cos (c+d x)}}\right )}{2 \sqrt {2} a^{3/2} d}+\frac {(21 A-14 B+12 C) \tan (c+d x)}{8 a d \sqrt {a+a \cos (c+d x)}}-\frac {(13 A-12 B+6 C) \sec (c+d x) \tan (c+d x)}{12 a d \sqrt {a+a \cos (c+d x)}}-\frac {(A-B+C) \sec ^2(c+d x) \tan (c+d x)}{2 d (a+a \cos (c+d x))^{3/2}}+\frac {(5 A-3 B+3 C) \sec ^2(c+d x) \tan (c+d x)}{6 a d \sqrt {a+a \cos (c+d x)}} \\
\end{align*}
Mathematica [A] (verified)
Time = 4.46 (sec) , antiderivative size = 249, normalized size of antiderivative = 0.88
\[
\int \frac {\left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^4(c+d x)}{(a+a \cos (c+d x))^{3/2}} \, dx=-\frac {\sec ^3(c+d x) \left (12 (17 A-13 B+9 C) \text {arctanh}\left (\sin \left (\frac {1}{2} (c+d x)\right )\right ) \cos ^5\left (\frac {1}{2} (c+d x)\right ) \cos ^3(c+d x)-3 \sqrt {2} (47 A-38 B+24 C) \text {arctanh}\left (\sqrt {2} \sin \left (\frac {1}{2} (c+d x)\right )\right ) \cos ^5\left (\frac {1}{2} (c+d x)\right ) \cos ^3(c+d x)+\frac {1}{4} \cos ^3\left (\frac {1}{2} (c+d x)\right ) (106 A-36 B+48 C+3 (55 A-26 B+36 C) \cos (c+d x)+(74 A-36 B+48 C) \cos (2 (c+d x))+63 A \cos (3 (c+d x))-42 B \cos (3 (c+d x))+36 C \cos (3 (c+d x))) \sin \left (\frac {1}{2} (c+d x)\right )\right )}{12 d (a (1+\cos (c+d x)))^{3/2} \left (-1+\sin ^2\left (\frac {1}{2} (c+d x)\right )\right )}
\]
[In]
Integrate[((A + B*Cos[c + d*x] + C*Cos[c + d*x]^2)*Sec[c + d*x]^4)/(a + a*Cos[c + d*x])^(3/2),x]
[Out]
-1/12*(Sec[c + d*x]^3*(12*(17*A - 13*B + 9*C)*ArcTanh[Sin[(c + d*x)/2]]*Cos[(c + d*x)/2]^5*Cos[c + d*x]^3 - 3*
Sqrt[2]*(47*A - 38*B + 24*C)*ArcTanh[Sqrt[2]*Sin[(c + d*x)/2]]*Cos[(c + d*x)/2]^5*Cos[c + d*x]^3 + (Cos[(c + d
*x)/2]^3*(106*A - 36*B + 48*C + 3*(55*A - 26*B + 36*C)*Cos[c + d*x] + (74*A - 36*B + 48*C)*Cos[2*(c + d*x)] +
63*A*Cos[3*(c + d*x)] - 42*B*Cos[3*(c + d*x)] + 36*C*Cos[3*(c + d*x)])*Sin[(c + d*x)/2])/4))/(d*(a*(1 + Cos[c
+ d*x]))^(3/2)*(-1 + Sin[(c + d*x)/2]^2))
Maple [B] (warning: unable to verify)
Leaf count of result is larger than twice the leaf count of optimal. \(2412\) vs. \(2(249)=498\).
Time = 20.13 (sec) , antiderivative size = 2413, normalized size of antiderivative =
8.50
| | |
| method | result | size |
| | |
| parts |
\(\text {Expression too large to display}\) |
\(2413\) |
| default |
\(\text {Expression too large to display}\) |
\(2993\) |
| | |
|
|
|
|
[In]
int((A+B*cos(d*x+c)+C*cos(d*x+c)^2)*sec(d*x+c)^4/(a+cos(d*x+c)*a)^(3/2),x,method=_RETURNVERBOSE)
[Out]
1/6*A*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*(1632*2^(1/2)*ln(2*(2*a^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)+2*a)/cos(1/2
*d*x+1/2*c))*cos(1/2*d*x+1/2*c)^8*a-1128*ln(4/(2*cos(1/2*d*x+1/2*c)+2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)+2^(
1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)+2*a))*cos(1/2*d*x+1/2*c)^8*a-1128*ln(-4/(2*cos(1/2*d*x+1/2*c)-2^(1
/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)-2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)-2*a))*cos(1/2*d*x+1/2*c)^8*a
-2448*2^(1/2)*ln(2*(2*a^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)+2*a)/cos(1/2*d*x+1/2*c))*cos(1/2*d*x+1/2*c)^6*a+5
04*2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)*cos(1/2*d*x+1/2*c)^6+1692*ln(4/(2*cos(1/2*d*x+1/2*c)+2^(1/2)
)*(2^(1/2)*a*cos(1/2*d*x+1/2*c)+2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)+2*a))*cos(1/2*d*x+1/2*c)^6*a+16
92*ln(-4/(2*cos(1/2*d*x+1/2*c)-2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)-2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a
^(1/2)-2*a))*cos(1/2*d*x+1/2*c)^6*a+1224*2^(1/2)*ln(2*(2*a^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)+2*a)/cos(1/2*d
*x+1/2*c))*a*cos(1/2*d*x+1/2*c)^4-608*2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)*cos(1/2*d*x+1/2*c)^4-846*
ln(4/(2*cos(1/2*d*x+1/2*c)+2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)+2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/
2)+2*a))*cos(1/2*d*x+1/2*c)^4*a-846*ln(-4/(2*cos(1/2*d*x+1/2*c)-2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)-2^(1/2)
*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)-2*a))*cos(1/2*d*x+1/2*c)^4*a-204*2^(1/2)*ln(2*(2*a^(1/2)*(a*sin(1/2*d*
x+1/2*c)^2)^(1/2)+2*a)/cos(1/2*d*x+1/2*c))*a*cos(1/2*d*x+1/2*c)^2+218*cos(1/2*d*x+1/2*c)^2*(a*sin(1/2*d*x+1/2*
c)^2)^(1/2)*2^(1/2)*a^(1/2)+141*ln(4/(2*cos(1/2*d*x+1/2*c)+2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)+2^(1/2)*(a*s
in(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)+2*a))*cos(1/2*d*x+1/2*c)^2*a+141*ln(-4/(2*cos(1/2*d*x+1/2*c)-2^(1/2))*(2^(1
/2)*a*cos(1/2*d*x+1/2*c)-2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)-2*a))*cos(1/2*d*x+1/2*c)^2*a-12*2^(1/2
)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2))/a^(5/2)/cos(1/2*d*x+1/2*c)/(2*cos(1/2*d*x+1/2*c)+2^(1/2))^3/(2*cos(1
/2*d*x+1/2*c)-2^(1/2))^3/sin(1/2*d*x+1/2*c)/(a*cos(1/2*d*x+1/2*c)^2)^(1/2)/d+1/4*B*(a*sin(1/2*d*x+1/2*c)^2)^(1
/2)*(76*ln(2/(2*cos(1/2*d*x+1/2*c)+2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)+2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/
2)*a^(1/2)+2*a))*2^(1/2)*cos(1/2*d*x+1/2*c)^6*a+76*ln(-2/(2*cos(1/2*d*x+1/2*c)-2^(1/2))*(2^(1/2)*a*cos(1/2*d*x
+1/2*c)-2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)-2*a))*2^(1/2)*cos(1/2*d*x+1/2*c)^6*a-208*ln(2*(a^(1/2)*
(a*sin(1/2*d*x+1/2*c)^2)^(1/2)+a)/cos(1/2*d*x+1/2*c))*cos(1/2*d*x+1/2*c)^6*a-76*2^(1/2)*ln(2/(2*cos(1/2*d*x+1/
2*c)+2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)+2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)+2*a))*cos(1/2*d*x+1
/2*c)^4*a-76*2^(1/2)*ln(-2/(2*cos(1/2*d*x+1/2*c)-2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)-2^(1/2)*(a*sin(1/2*d*x
+1/2*c)^2)^(1/2)*a^(1/2)-2*a))*cos(1/2*d*x+1/2*c)^4*a-56*cos(1/2*d*x+1/2*c)^4*a^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)
^(1/2)+208*ln(2*(a^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)+a)/cos(1/2*d*x+1/2*c))*cos(1/2*d*x+1/2*c)^4*a+19*2^(1/
2)*ln(2/(2*cos(1/2*d*x+1/2*c)+2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)+2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^
(1/2)+2*a))*cos(1/2*d*x+1/2*c)^2*a+19*2^(1/2)*ln(-2/(2*cos(1/2*d*x+1/2*c)-2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*
c)-2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)-2*a))*cos(1/2*d*x+1/2*c)^2*a+44*cos(1/2*d*x+1/2*c)^2*a^(1/2)
*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)-52*ln(2*(a^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)+a)/cos(1/2*d*x+1/2*c))*cos(1/2
*d*x+1/2*c)^2*a-4*a^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2))/a^(5/2)/cos(1/2*d*x+1/2*c)/(2*cos(1/2*d*x+1/2*c)+2^(
1/2))^2/(2*cos(1/2*d*x+1/2*c)-2^(1/2))^2/sin(1/2*d*x+1/2*c)*2^(1/2)/(a*cos(1/2*d*x+1/2*c)^2)^(1/2)/d-1/2*C*(a*
sin(1/2*d*x+1/2*c)^2)^(1/2)*(6*2^(1/2)*ln(2/(2*cos(1/2*d*x+1/2*c)+2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)+2^(1/
2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)+2*a))*cos(1/2*d*x+1/2*c)^4*a+6*2^(1/2)*ln(-2/(2*cos(1/2*d*x+1/2*c)-2
^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)-2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)-2*a))*cos(1/2*d*x+1/2*c)^
4*a-18*ln(2*(a^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)+a)/cos(1/2*d*x+1/2*c))*cos(1/2*d*x+1/2*c)^4*a-3*2^(1/2)*ln
(2/(2*cos(1/2*d*x+1/2*c)+2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)+2^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)
+2*a))*cos(1/2*d*x+1/2*c)^2*a-3*2^(1/2)*ln(-2/(2*cos(1/2*d*x+1/2*c)-2^(1/2))*(2^(1/2)*a*cos(1/2*d*x+1/2*c)-2^(
1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^(1/2)-2*a))*cos(1/2*d*x+1/2*c)^2*a-6*cos(1/2*d*x+1/2*c)^2*a^(1/2)*(a*sin
(1/2*d*x+1/2*c)^2)^(1/2)+9*ln(2*(a^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2)+a)/cos(1/2*d*x+1/2*c))*cos(1/2*d*x+1/2
*c)^2*a+a^(1/2)*(a*sin(1/2*d*x+1/2*c)^2)^(1/2))/a^(5/2)/cos(1/2*d*x+1/2*c)/(2*cos(1/2*d*x+1/2*c)-2^(1/2))/(2*c
os(1/2*d*x+1/2*c)+2^(1/2))/sin(1/2*d*x+1/2*c)*2^(1/2)/(a*cos(1/2*d*x+1/2*c)^2)^(1/2)/d
Fricas [A] (verification not implemented)
none
Time = 0.42 (sec) , antiderivative size = 402, normalized size of antiderivative = 1.42
\[
\int \frac {\left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^4(c+d x)}{(a+a \cos (c+d x))^{3/2}} \, dx=\frac {12 \, \sqrt {2} {\left ({\left (17 \, A - 13 \, B + 9 \, C\right )} \cos \left (d x + c\right )^{5} + 2 \, {\left (17 \, A - 13 \, B + 9 \, C\right )} \cos \left (d x + c\right )^{4} + {\left (17 \, A - 13 \, B + 9 \, C\right )} \cos \left (d x + c\right )^{3}\right )} \sqrt {a} \log \left (-\frac {a \cos \left (d x + c\right )^{2} - 2 \, \sqrt {2} \sqrt {a \cos \left (d x + c\right ) + a} \sqrt {a} \sin \left (d x + c\right ) - 2 \, a \cos \left (d x + c\right ) - 3 \, a}{\cos \left (d x + c\right )^{2} + 2 \, \cos \left (d x + c\right ) + 1}\right ) + 3 \, {\left ({\left (47 \, A - 38 \, B + 24 \, C\right )} \cos \left (d x + c\right )^{5} + 2 \, {\left (47 \, A - 38 \, B + 24 \, C\right )} \cos \left (d x + c\right )^{4} + {\left (47 \, A - 38 \, B + 24 \, C\right )} \cos \left (d x + c\right )^{3}\right )} \sqrt {a} \log \left (\frac {a \cos \left (d x + c\right )^{3} - 7 \, a \cos \left (d x + c\right )^{2} + 4 \, \sqrt {a \cos \left (d x + c\right ) + a} \sqrt {a} {\left (\cos \left (d x + c\right ) - 2\right )} \sin \left (d x + c\right ) + 8 \, a}{\cos \left (d x + c\right )^{3} + \cos \left (d x + c\right )^{2}}\right ) + 4 \, {\left (3 \, {\left (21 \, A - 14 \, B + 12 \, C\right )} \cos \left (d x + c\right )^{3} + {\left (37 \, A - 18 \, B + 24 \, C\right )} \cos \left (d x + c\right )^{2} - 6 \, {\left (A - 2 \, B\right )} \cos \left (d x + c\right ) + 8 \, A\right )} \sqrt {a \cos \left (d x + c\right ) + a} \sin \left (d x + c\right )}{96 \, {\left (a^{2} d \cos \left (d x + c\right )^{5} + 2 \, a^{2} d \cos \left (d x + c\right )^{4} + a^{2} d \cos \left (d x + c\right )^{3}\right )}}
\]
[In]
integrate((A+B*cos(d*x+c)+C*cos(d*x+c)^2)*sec(d*x+c)^4/(a+a*cos(d*x+c))^(3/2),x, algorithm="fricas")
[Out]
1/96*(12*sqrt(2)*((17*A - 13*B + 9*C)*cos(d*x + c)^5 + 2*(17*A - 13*B + 9*C)*cos(d*x + c)^4 + (17*A - 13*B + 9
*C)*cos(d*x + c)^3)*sqrt(a)*log(-(a*cos(d*x + c)^2 - 2*sqrt(2)*sqrt(a*cos(d*x + c) + a)*sqrt(a)*sin(d*x + c) -
2*a*cos(d*x + c) - 3*a)/(cos(d*x + c)^2 + 2*cos(d*x + c) + 1)) + 3*((47*A - 38*B + 24*C)*cos(d*x + c)^5 + 2*(
47*A - 38*B + 24*C)*cos(d*x + c)^4 + (47*A - 38*B + 24*C)*cos(d*x + c)^3)*sqrt(a)*log((a*cos(d*x + c)^3 - 7*a*
cos(d*x + c)^2 + 4*sqrt(a*cos(d*x + c) + a)*sqrt(a)*(cos(d*x + c) - 2)*sin(d*x + c) + 8*a)/(cos(d*x + c)^3 + c
os(d*x + c)^2)) + 4*(3*(21*A - 14*B + 12*C)*cos(d*x + c)^3 + (37*A - 18*B + 24*C)*cos(d*x + c)^2 - 6*(A - 2*B)
*cos(d*x + c) + 8*A)*sqrt(a*cos(d*x + c) + a)*sin(d*x + c))/(a^2*d*cos(d*x + c)^5 + 2*a^2*d*cos(d*x + c)^4 + a
^2*d*cos(d*x + c)^3)
Sympy [F]
\[
\int \frac {\left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^4(c+d x)}{(a+a \cos (c+d x))^{3/2}} \, dx=\int \frac {\left (A + B \cos {\left (c + d x \right )} + C \cos ^{2}{\left (c + d x \right )}\right ) \sec ^{4}{\left (c + d x \right )}}{\left (a \left (\cos {\left (c + d x \right )} + 1\right )\right )^{\frac {3}{2}}}\, dx
\]
[In]
integrate((A+B*cos(d*x+c)+C*cos(d*x+c)**2)*sec(d*x+c)**4/(a+a*cos(d*x+c))**(3/2),x)
[Out]
Integral((A + B*cos(c + d*x) + C*cos(c + d*x)**2)*sec(c + d*x)**4/(a*(cos(c + d*x) + 1))**(3/2), x)
Maxima [F(-2)]
Exception generated. \[
\int \frac {\left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^4(c+d x)}{(a+a \cos (c+d x))^{3/2}} \, dx=\text {Exception raised: RuntimeError}
\]
[In]
integrate((A+B*cos(d*x+c)+C*cos(d*x+c)^2)*sec(d*x+c)^4/(a+a*cos(d*x+c))^(3/2),x, algorithm="maxima")
[Out]
Exception raised: RuntimeError >> ECL says: THROW: The catch RAT-ERR is undefined.
Giac [A] (verification not implemented)
none
Time = 0.68 (sec) , antiderivative size = 462, normalized size of antiderivative = 1.63
\[
\int \frac {\left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^4(c+d x)}{(a+a \cos (c+d x))^{3/2}} \, dx=\frac {\frac {6 \, \sqrt {2} {\left (17 \, A \sqrt {a} - 13 \, B \sqrt {a} + 9 \, C \sqrt {a}\right )} \log \left (\sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )}{a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} - \frac {6 \, \sqrt {2} {\left (17 \, A \sqrt {a} - 13 \, B \sqrt {a} + 9 \, C \sqrt {a}\right )} \log \left (-\sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )}{a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} - \frac {3 \, {\left (47 \, A - 38 \, B + 24 \, C\right )} \log \left ({\left | \frac {1}{2} \, \sqrt {2} + \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right )}{a^{\frac {3}{2}} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} + \frac {3 \, {\left (47 \, A - 38 \, B + 24 \, C\right )} \log \left ({\left | -\frac {1}{2} \, \sqrt {2} + \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right )}{a^{\frac {3}{2}} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} - \frac {12 \, \sqrt {2} {\left (A \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - B \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + C \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )} a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} - \frac {2 \, \sqrt {2} {\left (204 \, A \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 120 \, B \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 96 \, C \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 176 \, A \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 96 \, B \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 96 \, C \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 45 \, A \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 18 \, B \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 24 \, C \sqrt {a} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (2 \, \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{3} a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{48 \, d}
\]
[In]
integrate((A+B*cos(d*x+c)+C*cos(d*x+c)^2)*sec(d*x+c)^4/(a+a*cos(d*x+c))^(3/2),x, algorithm="giac")
[Out]
1/48*(6*sqrt(2)*(17*A*sqrt(a) - 13*B*sqrt(a) + 9*C*sqrt(a))*log(sin(1/2*d*x + 1/2*c) + 1)/(a^2*sgn(cos(1/2*d*x
+ 1/2*c))) - 6*sqrt(2)*(17*A*sqrt(a) - 13*B*sqrt(a) + 9*C*sqrt(a))*log(-sin(1/2*d*x + 1/2*c) + 1)/(a^2*sgn(co
s(1/2*d*x + 1/2*c))) - 3*(47*A - 38*B + 24*C)*log(abs(1/2*sqrt(2) + sin(1/2*d*x + 1/2*c)))/(a^(3/2)*sgn(cos(1/
2*d*x + 1/2*c))) + 3*(47*A - 38*B + 24*C)*log(abs(-1/2*sqrt(2) + sin(1/2*d*x + 1/2*c)))/(a^(3/2)*sgn(cos(1/2*d
*x + 1/2*c))) - 12*sqrt(2)*(A*sqrt(a)*sin(1/2*d*x + 1/2*c) - B*sqrt(a)*sin(1/2*d*x + 1/2*c) + C*sqrt(a)*sin(1/
2*d*x + 1/2*c))/((sin(1/2*d*x + 1/2*c)^2 - 1)*a^2*sgn(cos(1/2*d*x + 1/2*c))) - 2*sqrt(2)*(204*A*sqrt(a)*sin(1/
2*d*x + 1/2*c)^5 - 120*B*sqrt(a)*sin(1/2*d*x + 1/2*c)^5 + 96*C*sqrt(a)*sin(1/2*d*x + 1/2*c)^5 - 176*A*sqrt(a)*
sin(1/2*d*x + 1/2*c)^3 + 96*B*sqrt(a)*sin(1/2*d*x + 1/2*c)^3 - 96*C*sqrt(a)*sin(1/2*d*x + 1/2*c)^3 + 45*A*sqrt
(a)*sin(1/2*d*x + 1/2*c) - 18*B*sqrt(a)*sin(1/2*d*x + 1/2*c) + 24*C*sqrt(a)*sin(1/2*d*x + 1/2*c))/((2*sin(1/2*
d*x + 1/2*c)^2 - 1)^3*a^2*sgn(cos(1/2*d*x + 1/2*c))))/d
Mupad [F(-1)]
Timed out. \[
\int \frac {\left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^4(c+d x)}{(a+a \cos (c+d x))^{3/2}} \, dx=\int \frac {C\,{\cos \left (c+d\,x\right )}^2+B\,\cos \left (c+d\,x\right )+A}{{\cos \left (c+d\,x\right )}^4\,{\left (a+a\,\cos \left (c+d\,x\right )\right )}^{3/2}} \,d x
\]
[In]
int((A + B*cos(c + d*x) + C*cos(c + d*x)^2)/(cos(c + d*x)^4*(a + a*cos(c + d*x))^(3/2)),x)
[Out]
int((A + B*cos(c + d*x) + C*cos(c + d*x)^2)/(cos(c + d*x)^4*(a + a*cos(c + d*x))^(3/2)), x)